b^2+3b=3b+4

Solution for b^2+3b=3b+4 equation:

Simplifying
b2 + 3b = 3b + 4

Reorder the terms:
3b + b2 = 3b + 4

Reorder the terms:
3b + b2 = 4 + 3b

Add '-3b' to each side of the equation.
3b + -3b + b2 = 4 + 3b + -3b

Combine like terms: 3b + -3b = 0
0 + b2 = 4 + 3b + -3b
b2 = 4 + 3b + -3b

Combine like terms: 3b + -3b = 0
b2 = 4 + 0
b2 = 4

Solving
b2 = 4

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Simplifying
b2 = 4

Take the square root of each side:
b = {-2, 2}